Sorry for spamming! View.addView() didn't work for me cause I forgot to implement the onLayout abstract method of the ViewGroup. Sorry again!
On máj. 14, 11:56, Kiripolszky Károly <[email protected]> wrote: > Helo Dear Reader! > > I'm trying to implement my custom interface for a drawing application > which contains an editor ViewGroup. The editor group moreover contains > a SurfaceView for holding the image and custom Views for toolbars. Now > I wanna make the toolbars ViewGroups as well, so I could make the > toolbar buttons as additional Views, each having their own event > handlers and drawing functions. I don't want to implement new GUI > components, but to build on Android API and only extend the drawing > and event handling functions of the View. This is necessary as I want > to display the toolbar ontop of the image so I need my customized > layout as well. > > My problem is that there is no such function > ViewGroup.addView(ViewGroup view), however the documentation states on > the page about the View: > > "The ViewGroup subclass is the base class for layouts, which are > invisible containers that hold other Views (or other ViewGroups) and > define their layout properties." > > Could someone please explain how to nest a ViewGroup in another > ViewGroup? > > -- > You received this message because you are subscribed to the Google > Groups "Android Beginners" group. > > NEW! Try asking and tagging your question on Stack Overflow > athttp://stackoverflow.com/questions/tagged/android > > To unsubscribe from this group, send email to > [email protected] > For more options, visit this group > athttp://groups.google.com/group/android-beginners?hl=en -- You received this message because you are subscribed to the Google Groups "Android Beginners" group. NEW! Try asking and tagging your question on Stack Overflow at http://stackoverflow.com/questions/tagged/android To unsubscribe from this group, send email to [email protected] For more options, visit this group at http://groups.google.com/group/android-beginners?hl=en
